Question

solve 4^(x-2)-2^(x+1)=0

Answer 1

4^(x-2)=2^(x+1)
2^2 (x-2)=2^(x+1)
2x-4=x+1
2x-x=1+4
x=5
... ......here is your ans

Answer 2

Hey dear !!


Here is yr answer...

$= > {4}^{x - 2} - {2}^{x + 1} = 0 \\ \\ = > ( {2}^{2} )^{x - 2} = {2}^{x + 1} \\ \\ = > { 2}^{2(x - 2)} = {2}^{x + 1} \\ \\ = > {2}^{2x - 4} = 2^{x + 1} \\ \\ here \: bases \: are \: equal \: so \: the \: powers \: must \: be \: equal \\ \\ = > 2x - 4 = x + 1 \\ \\ = > 2x - x = 1 + 4 \\ \\ = > x = 5$

Therefore, value of x = 5


Hope it hlpz....