Question

car travels at 54 km per hour for first 20 seconds 36 km per hour for next 30 sec and finally 18 km per hour for next 10 seconds find its average speed

Answer 1

54 km/hr = 54 x 5/18 = 15 m/s
36 km/hr = 36 x 5/18 = 10 m/s
18 km/hr = 18 x 5/18 = 5 m/s

1st Case ---
Speed = 15m/s
Time = 20 s
Distance = Speed x Time = 15 x 20 = 300 m

2nd Case ---
Speed = 10 m/s
Time = 30 sec
Distance = 10 x 30 = 300 m

3rd Case ---
Speed = 5 m/s
Time = 10s
Distance = 5 x 10 = 50 m

Now Total Distance = 300 + 300 + 50 = 650 m
Total time = 20 + 30 + 10 = 60 s

Average Speed = 650/60 = 65/6 m/s

Hope This Helps You! :-)

Answer 2

Hey there!

Formula used:

• Distance = speed * time

• Speed ( in 1 km/h) = 5 /18 (in 1 m/s)

Distance covered when car travels at 54 km/h for first 20 s:

Speed = 54 km / h

           = 54 *( 5/18) m/s

           = 15 m/s

Distance (d₁) = speed * time

                    = 15 * 20 = 300 m

Distance covered when car travels at 36 km/h for  30 s:

S = 36 km/h = 36 * (5/18) m / s  = 10 m/s

d₂ = v * t = 10 * 30 = 300 m

Distance covered when car travels at 18 km/h for  10 s:

S = 18 km/h = 18*(5/18) m/s = 5 m/s

d₃ = v * t = 5 * 10 = 50 m

Average speed = Total distance(d₁ + d₂ + d₃) / Total time

                           = (300 + 300 + 50) m / (20 + 30 + 10) s

                           = (650 m) / 60 s

                           = 10.83 m/s  (←Answer)

Good day!