please solve this maths problem... i will definately mark your ans as brainliest..get more points.. thankyou.. your lovingly friend Nevika.. : )
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we know that if a diagonal divides a quadrilateral into two equal parts i.e two congruent triangles then the quadrilateral is a parallelogram
now the diagonals of a parallelogram bisect each other
so DB bisects AC it is said the diagonal of a quadrilateral divide it into two equal parts. now one diagonal of a quadrilateral divide it into two triangles and since it is given that parts I.e triangles are equal so they are congruent
you should read the theorems of the parallelogram dear
now the diagonals of a parallelogram bisect each other
so DB bisects AC it is said the diagonal of a quadrilateral divide it into two equal parts. now one diagonal of a quadrilateral divide it into two triangles and since it is given that parts I.e triangles are equal so they are congruent
you should read the theorems of the parallelogram dear
Nevika1:
broke and yashi?
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Let the AC and BD intersect at o
Ar(AOD)=Ar(DOC) ( the medium of triangle divides it into two equal part of equal area (1)
Similarly
Ar(AOB)=ArBOC) (2)
Adding (1) and (2) eq we get
Ar(ABD)=Ar(BCD)
We conclude that diagonal AC divides the quadrilateral into two parts of equal area then it will surely the parallelogram
So
Ar(AOD)=Ar(DOC) ( the medium of triangle divides it into two equal part of equal area (1)
Similarly
Ar(AOB)=ArBOC) (2)
Adding (1) and (2) eq we get
Ar(ABD)=Ar(BCD)
We conclude that diagonal AC divides the quadrilateral into two parts of equal area then it will surely the parallelogram
So
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