Question

Carbide tool is used to machine a 30 mm diameter steel shaft at a spindle speed of 1000 revolutions per minute. the cutting speed of the above turning operation is:

Answer 1

The cutting speed is determined by the hardness of the material. The harder the material, the slower the cutting speed; faster for softer materials.
The cutting tool hardness will also have an affect on cutting speed. The harder the drill tool, the faster the cutting speed.
Cutting speed can be found using this equation:

 f = N × fr where:

 f = calculated linear feed rate of the drill [in/min]
N = spindle speed [rpm]
fr = feed per revolution of the drill [in/rev]

Answer 2

actually, cutting speed of turning operation is given by
$\bold{V_c=\frac{\pi\times D \times n}{1000}}$
Here, Vc is the cutting speed , D is diameter , n is the spindle speed

Given,
D = 30mm = 30 × 10⁻³m = 3 × 10⁻²m
n = 1000 revolution per minutes = 1000/60 rev/sec
∴Vc = π × 3 × 10⁻² × 1000/60/1000 = π × 3 × 10⁻²/60
Vc = 5π × 10⁻⁴ m/s = 1.57 × 10⁻³ m/s

Hence, cutting speed is 1.57 × 10⁻³ m/s