Carbon dioxide contains 27.27% of carbon , carbon disulphide contains 15.79% of carbon and sulphur dioxide contains 50% of sulphur. Prove/show these figures in agreement with the law of reciprocal proportions
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Answer: In CO
2
, 27.27% C and 72.73% O is present.
Ratio of C to O=C:O=27.27:72.73=1:2667⟶(i)
In CS
2
, 15.97% C and 84.03% of S is present.
Ratio of C$toS=C:S$$
1g of C combines with =
15.79
84.21
=5.33g of S⟶(ii)
The ratio of different masses of S&O combining with fixed mass of C is 5.33:2.67 i.e. 2:1⟶(iii)
In SO
2
, 50% of sand 50% of O is present.
∴ Rate of S to O=50:50=1:1⟶(iv)
The data illustrates the law of reciprocal proportions.
The ratio of different masses of S and O combining with fixed mass of carbon is a simple whole number.
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