Carbon is found to form two oxides which contains 42.9%and 27.3% of carbon show that these figures illustrate the law of multiple proportions
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RAM Carbon=12 Oxygen=16
The two oxides are CO and CO2
therefore RFM respectively are 28 and 44
Hence percentage composition of C is 42.9 and 27.3 respectively
The two oxides are CO and CO2
therefore RFM respectively are 28 and 44
Hence percentage composition of C is 42.9 and 27.3 respectively
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Answer:
Explanation:
In 100 g of the first compound (100 is chosen to make calculations easier) there are
57.1 g O and 42.9 g C.
The mass of O per gram C is: 57.1 g O / 42.9 g C = 1.33 g O per g CIn
the 100 g of the second compound, there are 72.7 g O and 27.3 g C. The mass of oxygen per gram of carbon is:72.7 g O / 27.3 g C = 2.66 g O per g C
Dividing the mass O per g C of the second (larger value) compound:
2.66 / 1.33 = 2
Which mean that the masses of oxygen that combine with carbon are in a 2:1 ratio.
The whole-number ratio is consistent with the Law of Multiple
Thanku....
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