Carbon
so) Having % of 42 10% H > 6:48.1
o = 51.42% Find the empherical
Formula
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This shows H: O: C: = 2 : 1 :1 That is empirical formula no. of oxygen atoms = no. of carbon atoms and number of hydrogen atoms is twice the number of oxygen atoms ∴ 2 x oxygen atoms = hydrogen atoms H = 2 x 12 = 24 Oxygen atoms = carbon atoms = 12 (given) ∴ Empirical formula = C12 H24 O12
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