Cards marked with number 7, 8, 9, ... , 25 are placed in a box. If a card is drawn randomly from the box, find
the probability that the selected card bears a prime number?
Answers
Answered by
2
6 are total prime numbers
18 are total numbers from 7 to 25
probability=no. of outcomes/total outcomes
=6/19
18 are total numbers from 7 to 25
probability=no. of outcomes/total outcomes
=6/19
plz answer this qn
9552.....
the numbers are S = {11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60}. n(S) = 50. take that event to drawn the an odd card as A. A={11,13,15,17,19,21,23,25,27,29,31,33,35,37,39,41,43,45,47,49,51,53,55,57,59}. n(A) = 25. so. P(A) = n(A)/n(S). p(A)=25/50.
take that event to drawn the perfect sqaure card as B. B = {16,25,36,49}. n(B) = 4. P(B) = n(B)/n(S). P(B) = 4/25
take that event to drawn the card which is divisible by 5 as C. C = {15,20,25,30,35,40,45,50,55,60}. n(C) = 10. P(C) = n(C)/n(S). P(C) = 10/50
ok next one??
take that event to drawn the card which is prime number as D. D = { 11,13,17,19,23,29,31,37,41,43,47,53,59}. n(D) = 13. P(D) = 13/50
2nd one is 4/59
sorry 4/50
Answered by
2
the numbers are
S = {7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25}
n(S) = 19
take the event of to drawn prime numbers card as A
A= {7,11,1317,19,23}
n(A) = 6
the probability is
P(A) = n(A)/n(s)
P(A) = 6 / 19
S = {7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25}
n(S) = 19
take the event of to drawn prime numbers card as A
A= {7,11,1317,19,23}
n(A) = 6
the probability is
P(A) = n(A)/n(s)
P(A) = 6 / 19
tnx
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a.an odd number
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