Question

Cards numbered 2 to 101 are placed in a box. A card is selected at random from the box, find the probability that the card selected. (i) has a number which is a perfect square. (ii) has an odd number which is not less than 70

Answer 1

Total no of cards=101-2+1=100
i)probalility of getting a perfect square=9/100=0.09
ii)Probalility of getting a odd number not less than 70=16/100=0.16

Answer 2

Answer:

The probability of getting a number which is a perfect square.= $\frac{9}{100}$ and probability of getting an odd number which is not less than 70= $\frac{16}{100}$

Step-by-step explanation:

We are given that Cards numbered 2 to 101 are placed in a box.

So, total no. of cards = 100

Now we are supposed to find the probability that the card selected has a number which is a perfect square.

So, perfect squares between 2 and 101 are {4,9,16,25,36,49,64,81,100}

No. of cards of perfect squares = 9

Total no. of cards = 100

So, probability of getting a number which is a perfect square.= $\frac{9}{100}$

Now we are supposed to find the probability that the card selected is has an odd number which is not less than 70

Odd numbers which is not less than 70 ={71,73,75,77,79,81,83,85,87,89,91,93,95,97,99,101}

No. of cards has an odd number which is not less than 70 = 16

So, probability of getting an odd number which is not less than 70= $\frac{16}{100}$

Thus the  probability of getting a number which is a perfect square.= $\frac{9}{100}$ and probability of getting an odd number which is not less than 70= $\frac{16}{100}$