Question

Carnot engine having an efficiency of 1 by 10 as heat engine is used as a refrigerator is the work done on the conductor stencil the amount of the necklace of the rosary at lower temperature is.

Answer 1

Effieciency of the Carnot Engine:

η \: = \: \frac{Work \: done}{Energy \: input}

\frac{1}{10} = \frac{10J}{Qinput}

η \: = 1 - \frac{Qoutput}{Qinput}

Now,

Qinput \: = 100J

And,

Qoutput = \frac{9}{10} \times 100J \\

Qoutput = 9 × 10

Qoutput = 90J

Therefore,

The amount of energy absorbed from the reservoir at low temperature is 90J.

Thus,

The answer is 90\: Joules.