Question

carry out the following activities to solve the equation 1. x-y+z=1, 2x-y=1,3x+3y-4z=2​

Answer 1

Answer:

the value of x is 1.

value of y is 1.

value of z is 1.

Step-by-step explanation:

to solve the given equation, take these equations as:

x-y+z=1...(i)

2x-y=1...(ii)

3x+3y-4z=2...(iii)

from eq(i) take the value of x i.e.,

x=1+y-z

now put the value of x in eq(ii). We get,

2(1+y-z)-y=1

2+2y-2z-y=1

2+y-2z=1

y=-1+2z

y=2z-1

now put the value of y in eq(i)

x-(2z-1)+z=1

x-2z+1+z=1

x-z+1=1

x-z=0

x=z

put x=z and y=2z-1 in eq(iii)

we get,

3(z)+3(2z-1)-4z=2

3z+6z-3-4z=2

5z=2+3

Z=1

As x=z, so x=1

Now, put value of x=1 and z=1 in eq(i)

1-y+1=1

y=1

Hence, the value of x=1, y=1 ,z=1

To verify, your answer put values of x,y,z in any of the given equation.