Cars moving along a straight line at a speed of 54km/hr stop in 5s after the brakes are applied. (a) Find the acceleration?
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Answered by
3
54kmph = 15m/s
v(final) = v(initial) - a*t
0 = 15 - a * 5
a = 3m/s^2
v(final) = v(initial) - a*t
0 = 15 - a * 5
a = 3m/s^2
Answered by
6
U = 54 km/h = 15m/s
V = 0(as the car stopped at the end)
v = u +at ( 1st equation of motion)
0 = 15 + 5a
5a = -15
a = -15/5 m/s
a = -3 m/s
Therefore the car retards with 3 m/s
V = 0(as the car stopped at the end)
v = u +at ( 1st equation of motion)
0 = 15 + 5a
5a = -15
a = -15/5 m/s
a = -3 m/s
Therefore the car retards with 3 m/s
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