Question

case.
9. Find the smallest number which when divided by 6, 8, 12, 15 and 20 leaves the same
remainder 5.​

Answer 1

Answer:

find the LCM of the numbers

6=2×3

8=2×2×2

12=2×2×3

15=3×5

20=2×2×5

LCM=2×2×2×3×5

=120

So the smallest number is 120+5=125

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