Math, asked by nitinchaudhari71963, 1 month ago

*Case Study : 1×4=4 In an examination hall ,students are seated at a distance ofONA virus pandemic .Let three students sit at a points A, B and C whose coordinates are (4, - 3) ,(7,3) and (8,5) resp. Based on the above information, answer the following questions. (i) The distance between A and C is (a) √5units (b) 4√5units (c) 3√5units (b) None of these (ii) If an invigilator at the point I , lying on the straight line Joining B and C such that it divides the distance Between them in the ratio 1: 2 .Then coordinates of I are (a) (22/3,11/3) (b) (23/3,13/3) (b) (6,1) (d) (9,1) iii) The ratio in which B divides the line segment joining A and C is (a) 2:1 (b) 3:1 (c) 1:2 (d) none of these iv) The mid-point of the line segment joining A and C is (a) (1,6) (b) (6,2) (c) (11/2,0) (d) none of these​

Answers

Answered by khushipandey132010
1

Answer:

According to the fig. A(3,4),B(6,7),C(9,4) and D(6,1) are the position of 4 friends .

If we join all these points then

By using distance formula

=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

AB=

(3−6)

2

+(4−7)

2

=

(−3)

2

+(−3)

2

=

9+9

=

18

=3

2

BC=

(6−9)

2

+(7−4)

2

=

(−3)

2

+(3)

2

=

9+9

=

18

=3

2

CB=

(9−6)

2

+(4−1)

2

=

(3)

2

+(3

2

)

=

9+9

=

18

=3

2

AD=

(3−6)

3

+(4−1)

2

=

−3)

2

+(3)

2

=

9+9

=

18

=3

2

if we join the point AC and BD than

DiagonalAC=

(3−9)

2

+(4−4)

2

=

(−6)

2

+(0)

2

=

36

=6

Diagonal BD=

(6−6)

2

+(7−1)

2

=

(0)

2

+(6)

2

=

36

=6

Hence all the sides of a quadrilateral are the same and the diagonals are also the same so ABCD is a square.

Hence Champa is correct.

solution

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Solution To Question ID 465327

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