Catherine bought an equal number of $11.00, $9 00, and $8.00 tickets for a concert. She spent $196 for all of the tickets. How many of each did she buy?
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1
Let x denote the equal number of tickets bought.
Since she bought equal number of $11.00, $9 00, and $8.00 tickets so money
spend is 11x+9x+8x = 28x
As she spend $196 in total so we must have
28x=196
x=196/28=7
Thus she bought 7 tickets of each type.
Since she bought equal number of $11.00, $9 00, and $8.00 tickets so money
spend is 11x+9x+8x = 28x
As she spend $196 in total so we must have
28x=196
x=196/28=7
Thus she bought 7 tickets of each type.
Answered by
0
Answer:
7 tickets at all
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