Question

Ccl4 + koh (excess) product, what is the product of reaction?

Answer 1

CCl4 + 4KOH - ––> CO2 + 4Cl- + 2H2O

Answer 2

It's a decomposition reaction:

CCl4 + 4 OH - ––> CO2 + 4Cl- + 2H2O

the OH- radical attacks nuceophillically Carbon tetrachloride but the Chloro-hydroxides, as for example CCl2(OH)2 are unstable and decompose down to CO2, the KOH turns into KCl, any KOH in excess will form K2(CO3) with the evolving CO2 .

May be this will help you . If there is anything wrong please comment .