Question

cd =10√2 find the value of angle cad​

Answer 1

Answer:

In ΔADB

we know that angle mathe on semicircle

90  

o

 so

∠ADB=90  

o

 

& CD∣∣AB'

∠CDA=∠DAB=25  

o

 

∠CDA=90+25=115

and ABCD is cyclic so

∠CAB+∠CDB=180  

o

 

∠CAD+∠DAB+115=180

∠CAD=180−115−25

∠CAD=40