CDEF is a cyclic quadrilateral. m∠CFE = 80°. m∠CEF = 45
a. What is the measure of ∠EDF?
b. Explain the steps you took to find the measure of ∠EDF.
Attachments:
Answers
Answered by
15
Heya !!!!
here is your answer !!!
in the given figure :-
CDEF is cyclic Quadrilateral !!
now ,
so the
< FEC =< FDC { 45 ° }
( angle in same sagement )
hence ,
< FDC =45 ° ------------------(1)
NOW ,
< CFE + < CDE = 180 °
{ cyclic Quadrilateral }
80 ° + < FDC + < FDE = 180 °
< FDC + < FDE = 100 .
now , from equation 1 we have
< FDC = 45 °
45 °. + < FDE = 100 °
=> < FDE =100 - 45 °
=> < FDE = 55°
hence the Value of X = 55°
hope it helps you dear !!!
thanks !!!
here is your answer !!!
in the given figure :-
CDEF is cyclic Quadrilateral !!
now ,
so the
< FEC =< FDC { 45 ° }
( angle in same sagement )
hence ,
< FDC =45 ° ------------------(1)
NOW ,
< CFE + < CDE = 180 °
{ cyclic Quadrilateral }
80 ° + < FDC + < FDE = 180 °
< FDC + < FDE = 100 .
now , from equation 1 we have
< FDC = 45 °
45 °. + < FDE = 100 °
=> < FDE =100 - 45 °
=> < FDE = 55°
hence the Value of X = 55°
hope it helps you dear !!!
thanks !!!
Answered by
3
Hi.
Good Question and Keep Progressing.
Here is your answer---
___________________
For the Measure of ∠EDF
In ΔCFE,
∠ FCE + ∠ CFE + ∠ CEF = 180° [ Angels Sum Property]
∠ FCE = 180° - (80° + 45°)
∠ FCE = 180° - 125°
∠ FCE = 55°
Now, ∠ FCE = ∠ EDF (Angels on the Same Segments are equals.)
= 55°
Thus, the measure of the ∠ EDF is 55°.
______________________
Hope it helps.
Have a nice day.
Good Question and Keep Progressing.
Here is your answer---
___________________
For the Measure of ∠EDF
In ΔCFE,
∠ FCE + ∠ CFE + ∠ CEF = 180° [ Angels Sum Property]
∠ FCE = 180° - (80° + 45°)
∠ FCE = 180° - 125°
∠ FCE = 55°
Now, ∠ FCE = ∠ EDF (Angels on the Same Segments are equals.)
= 55°
Thus, the measure of the ∠ EDF is 55°.
______________________
Hope it helps.
Have a nice day.
Similar questions