cell whose emf is 2V and internal resistance is 0.1 ohm is connected with a resistance of 3.9 ohm the voltage across the cell
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0.05 volts .this is the answer.If you have further doubt you can ask me.
rukkee:
can i get the solution please
net Resistance of ckt =4 ohm ,net emf = 2v, so using KVL current =0.5 A ,now drop across battery =I×R=0.5x0.1=.05 v
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