Math, asked by anisakabir56, 6 months ago

Centrilizer of group

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Answered by vaishno247
1

Answer:

In mathematics, especially group theory, the centralizer (also called commutant[1][2]) of a subset S of a group G is the set of elements of G that commute with each element of S, and the normalizer of S is the set of elements that satisfy a weaker condition. The centralizer and normalizer of S are subgroups of G, and can provide insight into the structure of G.

In mathematics, especially group theory, the centralizer (also called commutant[1][2]) of a subset S of a group G is the set of elements of G that commute with each element of S, and the normalizer of S is the set of elements that satisfy a weaker condition. The centralizer and normalizer of S are subgroups of G, and can provide insight into the structure of G.The definitions also apply to monoids and semigroups.

In mathematics, especially group theory, the centralizer (also called commutant[1][2]) of a subset S of a group G is the set of elements of G that commute with each element of S, and the normalizer of S is the set of elements that satisfy a weaker condition. The centralizer and normalizer of S are subgroups of G, and can provide insight into the structure of G.The definitions also apply to monoids and semigroups.In ring theory, the centralizer of a subset of a ring is defined with respect to the semigroup (multiplication) operation of the ring. The centralizer of a subset of a ring R is a subring of R. This article also deals with centralizers and normalizers in Lie algebra.

In mathematics, especially group theory, the centralizer (also called commutant[1][2]) of a subset S of a group G is the set of elements of G that commute with each element of S, and the normalizer of S is the set of elements that satisfy a weaker condition. The centralizer and normalizer of S are subgroups of G, and can provide insight into the structure of G.The definitions also apply to monoids and semigroups.In ring theory, the centralizer of a subset of a ring is defined with respect to the semigroup (multiplication) operation of the ring. The centralizer of a subset of a ring R is a subring of R. This article also deals with centralizers and normalizers in Lie algebra.The idealizer in a semigroup or ring is another construction that is in the same vein as the centralizer and normalizer.

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Answered by jmangaiyarkarasi93
0

The centralizer of an element z of a group G is the set of elements of G which commute with z,

C_G(z)={x in G,xz=zx}.

Likewise, the centralizer of a subgroup H of a group G is the set of elements of G which commute with every element of H,

C_G(H)={x in G, forall h in H,xh=hx}.

The centralizer always contains the group center of the group and is contained in the corresponding normalizer. In an Abelian group, the centralizer is the whole group.

example:

If G is a group, and H is a subgroup, then the normalizer of H in G is

NG(H)={g∈G∣g−1Hg=H},

and the centralizer is

CG(H)={g∈G∣gh=hg for all h∈H}.

It is easy to see that CG(H)⊆NG(H), but the converse need not hold.

For example, take G=S3, and let H={I,(1,2,3),(1,3,2)}.

What is CG(H)? It's the collection of all permutations that commute with I, with (1,2,3), and with (1,3,2). Since (1,2) does not commute with (1,2,3),

(1,2,3)(1,2)=(1,3)≠(2,3)=(1,2)(1,2,3),

then (1,2)∉CG(H). However, (1,2) does normalize H:

(1,2)−1I(1,2)(1,2)−1(1,2,3)(1,2)(1,2)−1(1,3,2)(1,2)=I∈H;=(1,3,2)∈H;=(1,2,3)∈H.

So (1,2)∈NG(H). Similarly, (1,3) and (2,3) are not in the centralizer, but are in the normalizer. H is contained in both.

For another example, take G=H=S3. Then the normalizer is all of G, because for every x,g∈G we have gxg−1∈G; but the centralizer is equal to the center (the set of things that commute with everything) and the center of G is just the identity.

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