Question

certain concrete mix needs cement, fine aggre
cate, and coarse aggregate in the ratio 1:2-4. If the
Contractor has 25 kg of fine aggregate how much
buantity of the cement and that of the coarse
aggregate is required to prepare the mix?​

Answer 1

Step-by-step explanation:

cement:fine aggregate:coarse aggregate::1:2:4

let cement be x

so fine aggregate=2x

coarse aggregate=4x

2x=25kg

=>12.5kg

cement=12.5kg

coarse aggregate=3×12.5kg=37.5 kg

<hope this helps....please mark as brainliest if it helps>

Answer 2

Answer: 12.5 kg and 50 kg respectively

Step-by-step explanation:

let common ration = x

now;

cement: fine aggregate: coarse aggregate = 1:2-4.

fraction of:

cement = 1/7x

fine aggregate = 2/7x

coarse aggregate = 4/7x

here fine agg = 2/7x =25 kg hence x =175/2

thus quantity of cement = 175/2*1/7=12.5kg

quantity of coarse aggregate = 175/2*4/7= 50kg