Question

Certain force acting on 20 kg mass changes it’s velocity from 5 ms to 2 ms calculate work done

Answer 1

Explanation:

let the force be F

work done=force×displacement

W=F×S

W=20×a(v^2-u^2)/2a

a-acceleration

v-final velocity

u-intial velocity

W=10(2^2-5^2)

=10(-21)

=-210 J