Certain force acting on a 20 kg mass changes its velocity from
5m/s to 2 m/s. Calculate the work done by the force
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Answer
- Work dine is -210 J
Explanation
Given
- A force is acting on a body of mass 20 kg
- It changes its velocity form 5 m/s to 2 m/s
To Find
- The work Done?
Formula
Kinetic Energy = ½mv² or ½mu²
Solution
So here we know that the change in the kinetic energy of the body will be the work done
Work Done
➝ Work = ½mv² - ½mu²
- v = 2 m/s
- u = 5 m/s
Initial Kinetic Energy
➝ ½mu²
➝ ½ × 20 × 5²
➝ ½×20×25
➝ 10×25
➝ 250 J
Final Kinetic Energy
➝ ½mv²
➝ ½×20×2²
➝ ½×20×4
➝ 10×4
➝ 40 J
Work Done by the body
➝ Initial-Final
➝ 40-250
➝ Work = -210 J
Here it is negative as it reduces the speed of the body
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