Certain force acting on a 20 kg mass changes
its velocity from 5 m/s to 12 m/s. Work done
by the force is _____ Joule.
Answers
Answered by
0
Using work energy theorem,
Work done= Change in KE.
Change in KE = 1/2×20(144-25)
=10×119= 1190J.
Answered by
0
Answer:
using the theorum of kinetic energy
Explanation:
work done=1/2×m×(v²-u²)
=1/2×20 kg×(144-25)m²/s²
10kg×119 m²/s²
=1190J
please mark me as brainliest
Similar questions