Physics, asked by khandelwalpranam431, 4 months ago

Certain force acting on a 20 kg mass changes
its velocity from 5 m/s to 12 m/s. Work done
by the force is _____ Joule.​

Answers

Answered by Sreejith12345
0

Using work energy theorem,

Work done= Change in KE.

Change in KE = 1/2×20(144-25)

=10×119= 1190J.

Answered by ayushi22aug
0

Answer:

using the theorum of kinetic energy

Explanation:

work done=1/2×m×(v²-u²)

=1/2×20 kg×(144-25)m²/s²

10kg×119 m²/s²

=1190J

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