Question

Certain sum on compound interest amounts 16200 rs. In 2 years at 12.5 p.C.P.A what is the principal

Answer 1

$a = p( 1 + \frac{r}{100} )^{2} \\ 16200 = p(1 + \frac{12.5}{100} )^{2} \\ 16200 = p(1 + \frac{1}{8} )^{2} \\ 16200 = p( \frac{9}{8} )^{2} \\ 16200 = p \times \frac{81}{64} \\ p = \frac{16200}{81} \times 64 \\ p = 64 \times 200 \\ p = 12800$