Math, asked by tanu63932, 1 year ago

(cesecA- sinA)(secA-cosA)​

Answers

Answered by Anonymous
4

Step-by-step explanation:

(cosec A - sin A )(sec A - cosA)

= {1/ sin A - sinA }{1/ cos A - cos A }

={(1-sin^2A)/sin A }{(1-cos^2A )/cosA}

= (cos^2A)/sinA • sin^2A/cosA

= cosA• sinA

Answered by gsantoshgpooja
0

cosecA×secA-cosecA×cosA-sinA×secA+sinA×cosA

=1/sinA×1/cosA-1/sinA×cosA-sinA×1/cosA+sinA×cosA

=1-cos^2A-sin^2A+sin^2A×cos^2a.

sinA×cosA

=1-(sin^2A+cos^2A)+sin^2A×cos^2A

sinA×cosA

=1-1+sinA×sinA×cosAcosA

sinA×cosA

=0+sinA×sinA×cosA×cosA

sinA×cosA

=sinA×sinA×cosA×cosA

sinA×cosA

=sinA×cosA

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