Question

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Answer 1

Answer:

9g.

Explanation:

The velocity gained by the body before entering into the sand :

Equating the energies  :   $mgh = \frac{1}{2}mv^{2}$

                                      => $v = \sqrt{18g }$     ---------(1)

After entering the sand, initial velocity = $v$

and final velocity = 0 and let the decceleration in the sand be "a".

Again equating the energies : $mah = \frac{1}{2}mv^{2}$

                                             => $(1)a=\frac{1}{2}( 18g)$

                                             => a = 9g.

Answer 2

Answer:

yes thet answer is absolutely correct