Question

ch-11 of maths class 8 ex 11.1 q 1​

Answer 1

Answer:

Hey there... Here is ur answer

Given:

Length of rectangle = l = 80 cm

side of square = a = 60 cm

Also, we know

Perimeter of rectangle = 2(l + b)

Area of rectangle = lb,

where l = length and b = breadth

Perimeter of square = 4a

area of square = a2 ,

where a is side of square.

Let breadth of the rectangle be b

∵ Perimeter of the rectangle = Perimeter of the square

∴ 2 × (80 + b) = 4 × 60

2 × (80 + b) = 240

(80 + b) = 240/2

80 + b = 120

b = 120 - 80

⇒ b = 40 m

Now, area of square = a2 = 602 = 3600 m2

And area of the rectangle = lb = 80 × 40 = 3200 m2

Clearly, area of square is greater.

Hope it helped

Answer 2

Answer:

The product of ,7k=6×7k=42k

Step-by-step explanation: