Math, asked by fhsjdicjxnzh, 1 month ago

Ch-14 Factorisation ​

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Answered by guptaamitx
0

Answer:

a. (6x-7y+5z)(6x-7y-5z)

b. (x²-1)(x²-9)

Step-by-step explanation:

a. 36x²-84xy+49y²-25z²

= [(6x)²-2(6x)(7y)+(7y)²] -(5z)²

[using identity (a-b)²= a²-2ab+b² and a²-b²= (a+b)(a-b)]

=(6x-7y)²- (5z)²

=(6x-7y+5z)(6x-7y-5z)

b. x⁴-10x²+9

=x⁴-x²-9x²+9 (using middle term split method)

=x²(x²-1)-9(x²-1)

= (x²-1)(x²-9)

Hope It Helps :)

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