Question

Ch 3 ex 3.3 question 3 ka 1 in math of class 10

Answer 1

According to my NCERT class 10th book. Question 3 First part is attached in attachment file.

Answer:

The numbers are 13 and 39.

Step-by-step explanation:

Let's assume the larger number to be x.

And

Smaller number to be y.

Difference between two numbers are 26

According to Question :

$x - y = 26$

$x = 26 + y \: \: \: \: \: \: { \red{\longrightarrow} \: equation \: 1}$

Also it's said that one number is three times the other.

So,

$x = 3y \: \: \: \: \: \: { \blue{\longrightarrow} \: equation \: 2}$

$\red{ \tt{Substituting \: value \: in \: equation 1}}$

$\red{ \tt{26 + y = 3y}}$

$\red{ \tt{ - 2y = - 26}}$

$\red{ \tt{y = \cancel\frac{ - 26}{ - 2} }}$

$\red{ \tt{y = 13}}$

$\blue{ \tt{substituting \: value \: of \: y \: in \: equation \: 2}}$

$\blue{ \tt{x = 3 \times 13}}$

$\blue{ \tt{x = 39}}$

$\green{ \bold{\tt{hence \: the \: number \: is \: 13 \: and \: 39}}}$