Ch 9 Quadrilateral ABCD a rhombus are ab =17CM and diaganol ac=16 CM find the length of bd classClass8th give solution
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ABCD is a rhombus
ab=bc=cd=ad=17
diagonal of rhombus are perpendicular bisector of each other
let the point of intersection be O
therefore, In triangle AOB
angle AOB =90°
AB^2 = AO^2+OB^2
17^2 = 8^2 + OB^2
289 - 64 = OB^2
OB^2 = 225
OB=15
But ,ob = 1/2 bd
therefore, bd = 2ob = 2×15 = 30 CM
ab=bc=cd=ad=17
diagonal of rhombus are perpendicular bisector of each other
let the point of intersection be O
therefore, In triangle AOB
angle AOB =90°
AB^2 = AO^2+OB^2
17^2 = 8^2 + OB^2
289 - 64 = OB^2
OB^2 = 225
OB=15
But ,ob = 1/2 bd
therefore, bd = 2ob = 2×15 = 30 CM
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