Question

Ch - Mensuration
Please Solve these questions​

Answer 1

Step-by-step explanation:

Q.6 ) Let the parallel sides of the trapezium-shaped field be

Let a=x and b=2x and h=100m

Then, its area.

= 2/1

(a+b)×hm^2

= 2/1

(x+2x)×100m ^2

=50×3xm ^2

=150xm /2

But it is given that the area of the field is 10500m^2

∴150x=10500

⇒x= 150 /10500

=70

∴ The length of the side along the river is 2×70, i.e., 140m.

Q.7)Let the length of one parallel side be x cm.

Then, the length of the other parallel side will be (x+6)cm

Area of trapezium = 1/2 × 9 × (x × x × 6)

=180 = 1/2 × 9 × (2x×6)

= 360 = 18x + 54

= 18x = 360 -54 =306

= x = 17cm

Thus, the two parallel sides are 17cm and 23cm

Q8)⇩⇩➘

$We \: divide \: the \: trapezium \: into  \: 3 parts:  \: 2 triangles \: and \: a \: rectangle.</p><p></p><p></p><p>Base \: of \: triangle =220−10=5 </p><p></p><p></p><p>Height \: of \: the \: triangle \: and \: rectangle \:  (h)2=132−52</p><p></p><p></p><p>⇒(h)2=144</p><p></p><p></p><p>⇒h=12</p><p></p><p></p><p>Area \: of \: trapezium =21×(sum \: of parallel \: sides) × (height)</p><p>                            =21×(10+20)×(12)</p><p></p><p></p><p>                            =180 sq.cm </p><p></p><p>$

180sq.cm

Q9.)TSA of cuboidal A = 2(lb+lh+bh)

$= 562 {0cm}^{2}$

TSA of Cuboidal B =2(lb+lh+bh)

$4416 {cm}^{2}$

Hope it helps..❤️

If possible pls mark as brainliest✌️❤️

Answer 2

Answer:

$\: \: \: \: \: \: \:$

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