Ch: Perimeter and Area
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2)area of square = s×s
=20×20
=400cm^2
area of FEA = 1/2×10×10
= 50cm^2
area of CBE = 1/2×10×20
=100cm^2
area of DCF =100 cm^2
therefore area of shaded part =150cm^2
=20×20
=400cm^2
area of FEA = 1/2×10×10
= 50cm^2
area of CBE = 1/2×10×20
=100cm^2
area of DCF =100 cm^2
therefore area of shaded part =150cm^2
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now,
2.
→ area of AEF =1/2×B×H
=1/2×10×10
=5×10
=50cm²
→ area of EBC=1/2×B×H
=1/2×10×20
=5×20
=100cm²
→ area of DFC=1/2×B×H
=1/2×10×20
=5×20
=100cm²
→ area of ABCD=side×side
=20×20
=400cm²
hence area of the shaded region=400-(50+100+100)
=400-250
=150cm²
hope this helps u...!
above part is in the pic...
2.
→ area of AEF =1/2×B×H
=1/2×10×10
=5×10
=50cm²
→ area of EBC=1/2×B×H
=1/2×10×20
=5×20
=100cm²
→ area of DFC=1/2×B×H
=1/2×10×20
=5×20
=100cm²
→ area of ABCD=side×side
=20×20
=400cm²
hence area of the shaded region=400-(50+100+100)
=400-250
=150cm²
hope this helps u...!
above part is in the pic...
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thank you for brainliest
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