Question

★CH3-CH2-1+KCN(alc) --> ‘A’ . Here ‘A’ is .
a) CH3-CH3-NC
B) CH3-CH2- CN
C) CH3-CN
D) CH3-NC
Don't dare to reply if you don't know the answer

Answer 1

Answer:

CH3-CH2- CN

CH CH CN

CH NC

CH CN

Answer 2

'A' is CH₃-CH₂-CN which is Option B.

• When alkyl bromides of the form R-X, where R is the alkyl group and X is the halogen group, react in the presence of KCN (alc.) (potassium cyanide), alkyl cyanides R-CN are formed as the major product, and potassium halide, K-X is formed as a by-product.

• CH₃-CH₂-Br + K-CN (alc.) → CH3₃CH2₂CN + K-Br

• Ethyl chloride reacts with potassium cyanide to form Ethyl Cyanide (CH₃-CH₂-CN) as the main product along with potassium bromide (K-Br) as a by-product.