ch3ch2ch2ch2ch2I ;ch3ch2ch2ch2ch2Cl .which compound undergoes faster SN2 reaction.
Anonymous:
Aren't both the compounds same?
No, sorry I saw I as Cl ka l
Answers
Answered by
0
It's easy..(CH3)2CHI will undergo an SN2 reaction more readily than(CH3)3CCH2I ...
(pardon me if you don't understand)..(because there no space!).. You can check the video for the full and complete explaination!!..
Hope this helps you out!!
(pardon me if you don't understand)..(because there no space!).. You can check the video for the full and complete explaination!!..
Hope this helps you out!!
Attachments:
YouTube link.....
wait a minute
I m seriously sorry, but could you please read the question once, what you hv said in your ans is totally correct
But this question needs a different approach
https://m.youtube.com/watch?v=NV40N14Oqe0
The ans is Ch3ch2ch2ch2ch2I because I is a better leaving group
hope this helps you out!!.. this is the link for the complete explaination
yes.....
Thanks.
can you mark as brainliest.. if you liked it!!
Answered by
3
Hey dear,
According to SN2 mechanism iodine group go to sn2 reaction.
Reason➖Reactivity order for the alkyl halides towards Sn2 reaction is R-I>R-Br>R-Cl>R-F. This can be explained by which halogen atom is a better leaving group compared to the other.
But in case of Aryl halides, where substitution occurs by SnAr mechanism, the order is reverse Ar-F>Ar-Cl>Ar-Br>Ar-I.
According to SN2 mechanism iodine group go to sn2 reaction.
Reason➖Reactivity order for the alkyl halides towards Sn2 reaction is R-I>R-Br>R-Cl>R-F. This can be explained by which halogen atom is a better leaving group compared to the other.
But in case of Aryl halides, where substitution occurs by SnAr mechanism, the order is reverse Ar-F>Ar-Cl>Ar-Br>Ar-I.
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