Question

Ch3Ch2CooAg ke naming

Answer 1

Answer:

the answer is -

Start with the acid CH3CH2COOH. This is clearly the one and only simple carboxylic acid derived from an unsubstituted propane chain, so it's

"Propan-" from the propane chain

plus "-oic acid" from the carboxyl group (we don't need a locant because there is only one place to fit that group)

= propanoic acid

Then the silver salt is silver propanoate, the "-ic acid" part becomes "-ate" just like inorganic salts.

Explanation:

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