Chemistry, asked by ayush672790, 9 months ago

CH3CH2OH IN THE PRESENCE OF ACIDIFIED K2Cr2O7

Answers

Answered by sreejakomirishetty

1

Answer:

Forms CH3CHO (ethanal) then forms ethanoic acid(CH3COOH)

Answered by Sreesha

0

Answer:

Forms ethanoic acid

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