Question

CH3CONH2 reacts with bromine in presence of KOH then product is

Answer 1

When CH3CONH2 , acetamide reacts with KOH. Br2, we get methylamine,  CH3NH2
The reaction is
CH3CONH2   −→−Br2KOH   CH3NH2  + KBr

Here the reaction begins with the reaction with Br2, leading to formation of isocyanate which further hydrolysis to give the desired product.