Question

CH4+202=CO2+2H2O ....FIND THE VALUE OF ΔH OF THE REACTION

Answer 1

Answer:

CHO + OX +2Ho2 ho ji fifth bodies before

Answer 2

Answer:

The enthalpy changes for the following reactions can be measured: CH4(g) + 2O2(g) --> CO2(g) + 2H2O(g) deltaH=-802.4KJ/mol-rxn CH3OH(g) + 3/2O2(g) --> CO2(g) + 2H2O(g) ...

The enthalpy changes for the following reactions can be measured:

CH4(g) + 2O2(g) --> CO2(g) + 2H2O(g) deltaH=-802.4KJ/mol-rxn

CH3OH(g) + 3/2O2(g) --> CO2(g) + 2H2O(g) deltaH=-676KJ/mol-rxn

Use these values and Hess's law to determine the enthalpy change for the reaction:

CH4(g) + 1/2O2(g) --> CH3OH(g)