ⓗⓔⓨ ⓜⓐⓣⓔ ! ___________________________________________________________________________
Challange for JEE STUDENTS
Solve the Series in terms of "n"
DON'T SPOIL....
BRAINLIST WITH 15 POINTS
# Zia
Attachments:
Answers
Answered by
0
1/(1+2+3...Tn = 1/( n)(n+1)/2
= 2/(n)(n+1)
= 2( 1/n(n+1))
= 2( (n+1) - n )/ n ( n+1)
= 2( 1/n - 1/( n+1))
Sn= 2( 1 - 1/2 + 1/2 - 1/3........1/n - 1/n+1)
= 2( 1 - 1/n+1)
= 2/(n)(n+1)
= 2( 1/n(n+1))
= 2( (n+1) - n )/ n ( n+1)
= 2( 1/n - 1/( n+1))
Sn= 2( 1 - 1/2 + 1/2 - 1/3........1/n - 1/n+1)
= 2( 1 - 1/n+1)
Similar questions