Question

##CHALLENGE FOR EVERYONE##
*LET'S SEE WHO CAN SOLVE THIS QUESTION*

Q. Solve the following equations by factorisation method:
${y}^{ \frac{2}{3} } - {2y}^{ \frac{1}{3} } = 15$

Answer 1

Thanks for the challenge :

♧♧HERE IS YOUR ANSWER♧♧

Given :

${y}^{ \frac{2}{3} } - {2y}^{ \frac{1}{3} } = 15 \: \: ......(i)$

Let us consider :

${y}^{ \frac{1}{3} } = x$

Then, (i) becomes :

x² - 2x = 15

=> x² - 2x - 15 = 0

=> x² - 5x + 3x - 15 = 0

=> x(x - 5) + 3(x - 5) = 0

=> (x - 5)(x + 3) = 0

So, either x - 5 = 0 or, x + 3 = 0

=> x = 5 or, x = - 3.

When, x = 5

${y}^{ \frac{1}{3} } = 5$

Taking cube, we get :

y = 5³

=> y = 125

Again, when x = - 3,

${y}^{ \frac{1}{3} } = - 3$

Taking cube, we get :

y = (- 3)³

=> y = - 27

Therefore, the required solution is

y = 125 and y = - 27.

♧♧HOPE THIS HELPS YOU♧♧

Answer 2

☺ ☺ ☺ Hope this Helps ☺ ☺ ☺