the present age of seeta and geeta are inratio 3:4. the product of their ages (in year) is 48. find the sum of their ages
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let age of sita be 3x and Geeta be 4x then,atq, 3x x 4x=48 so,12x=48 then,x=4. so 3x=12&4x=16 so 3x+4x=28
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let ages of seeta and geeta be 3x and 4x
3x*4x=48
12x=48
x=4
age of geeta=3x=3*4=12
age of seeta=4x=4*4=16
3x*4x=48
12x=48
x=4
age of geeta=3x=3*4=12
age of seeta=4x=4*4=16
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