Question

##CHALLENGE FOR EVERYONE##
*LET'S SEE WHO CAN SOLVE THIS QUESTION*

Q. A few friends went to a restaurant and had to pay a bill of ₹500. If two of them didn't pay their share then each of them had to pay ₹12.50 more to make up the deficit. How many friends were there?

*NO USELESS, COPIED ANS PLZ.*

Answer 1

let the total number of frnds be x.
let the shared amt. be y 
when there are x friends, share on each friend will be
=> y = 500/x                  ...........eq. (i)
when two frnds are not there then
=> (y + 12.5) = 500/(x - 2)
=> (y+12.5)(x-2) = 500
=>  xy - 2y + 12.5 x - 25 = 500
=>  xy - 2y + 12.5 x = 525
putting the value of y frm eq. (i)
=> x(500/x) - 2*(500/x) + 12.5 x = 525
=> 12.5x - 1000/x = 25
=> 12.5 x^2 - 1000 = 25x
=> x^2 - 80 = 2x
=> x^2 - 2x - 80
on solving it
=> x = 10 or -8
since no of frnd can't be negative
so the total number of frnds are 10

Answer 2

let the total number of frnds be x.

let the shared amt. be y 

when there are x friends, share on each friend will be

=> y = 500/x                  ...........eq. (i)

when two frnds are not there then

=> (y + 12.5) = 500/(x - 2)

=> (y+12.5)(x-2) = 500

=>  xy - 2y + 12.5 x - 25 = 500

=>  xy - 2y + 12.5 x = 525

putting the value of y frm eq. (i)

=> x(500/x) - 2*(500/x) + 12.5 x = 525

=> 12.5x - 1000/x = 25

=> 12.5 x^2 - 1000 = 25x

=> x^2 - 80 = 2x

=> x^2 - 2x - 80

on solving it

=> x = 10 or -8

since no of frnd can't be negative

so the total number of frnds are 10 pllleasr mark brainlist