Question

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Diameter of Cylinder a is 7 cm and height is 14 cm. diameter of Cylinder B is 14 cm and height is 7 cm. give volume of both cylinder. Suggest whose volume is greater. Also check that whose volume is big is its surface area is also great.

(Give diagrams if possible).

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Answer 1

Answer:

I am explain you don't worry ☺️

your first ans is A)= 539 cm3

your second ans is B) = 1078 cm3

Step-by-step explanation:

A) = h= 14 cm

r= 7/2

volume = πr2

= 22/7×7/2×7/2×14

=11×1×7×7

539 cm3

B)=

h= 7 cm

r= 14/2=7

volume πr2

= 22/7×7×7

=22×1×7×7

=1078cm3

Here is your Answer ☺️ and yap me as brainlist

Answer 2

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Solution :-

Volume of cylinder B is greater than that of cylinder A.

Volume of cylinder B is greater than that of cylinder A.We use the formulae:

$\bf \: v = \pi {r}^{2} h$

$\bf \: S=2πr(r+h)$

where,

where,V = volume of cylinder

S = surface are of cylinder

surface are of cylinderr = radius

= radiush = height

Cylinder A:

$\bf \: v \: = \pi {r}^{2} h \: ⇒v = \frac{22}{7} \times ( \frac{7}{2} ) {}^{2} \times 14 = 540$

$\bf \: s = 2\pi \ r(r + h)⇒s = 2 \times \frac{22}{7} \times \frac{7}{2} \times ( \frac{7}{2} + 14) = 385$

Cylinder B :

$\bf \: v \: = \pi {r}^{2} h \: ⇒v = \frac{22}{7} \times ( \frac{14}{2} ) {}^{2} \times 7 =1078$

$\bf \: s = 2\pi \ r(r + h)⇒s = 2 \times \frac{22}{7} \times \frac{14}{2} \times ( \frac{14}{2} + 7) = 616$

It's clear from the calculation, that, cylinder with greater volume has greater surface area i.e, cylinder B

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Diagram was on attachment :-

Hope you understand this concept :)