Science, asked by Anonymous, 6 months ago

☆challenge for mods/ stars☆


Question-

A force of 5 newtons gives a mass m1 an acceleration of 8m/s^2, and a mass m2 an acceleration of 24 m/s^2 . what acceleration would it give if the masses are tried together? ​

Answers

Answered by Anonymous
3

GiveN :

  • Force (F) = 5 N
  • Acceleration of 1st object (a1) = 8 m/s²
  • Mass of 1st object = m1
  • Acceleration of 2nd object (a2) = 24 m/s²
  • Mass of 2nd Object = m2

To FinD :

  • Acceleration when masses are tied together.

SolutioN :

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\implies \sf{F = m_1 a_1}

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\implies \sf{5 = m_1 \times 8}

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\implies \sf{m_1 = \dfrac{5}{8}}

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\underline {\sf{\therefore \: Mass\ of\ First\ object\ is\ \dfrac{5}{8}\ kg}}

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ㅤㅤㅤㅤ\underbrace{\sf{For\ Second\ Object}}

\implies \sf{F = m_2 a_2}

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\implies \sf{5 = 24m_2}

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\implies \sf{m_2 = \dfrac{5}{24}}

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\underline {\sf{\therefore\ Mass\ of\ second\ object\ \dfrac{5}{24}\ kg}}

_________________________

Now, if masses are tied together :

\implies \sf{m = m_1 + m_2}

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\implies \sf{m = \dfrac{5}{8} + \dfrac{5}{24}}

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\implies \sf{m = \dfrac{5(3) + 5(1)}{24}}

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\implies \sf{m = \dfrac{15 + 5}{24}}

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\implies \sf{m = \dfrac{20}{24}}

_________________

Now, acceleration of objects :

\implies \sf{F = ma}

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\implies \sf{a = \dfrac{F}{m}}

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\implies \sf{a = \dfrac{5}{\dfrac{20}{24}}}

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\implies \sf{a = \dfrac{24 \times 5}{20}}

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\implies \sf{a = \dfrac{24}{4}}

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\implies \sf{a = 6}

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\therefore Acceleration when masses are tied together is 6 m/s².

Answered by Anonymous
11

Answer:

 1) In the first case :

Force,  F = 5 N

Mass,  m = m1 (To be calculated)

And,

Acceleration, a =  8 m/s^2

Now,

 F = m × a

So,

 5 = m1 × 8

And, m1 = \frac{5}{8} kg

m1 = 0.635kg

Thus, the mass m1 is 0.625kg.

______________________________________

 2) In the second case :

Force,  F = 5 N

Mass,  m = m2 (To be calculated)

And,

Acceleration, a =  8 m/s^2

Now,

 F = m × a

So,

 5 = m2 × 24

and, m2 =

 \frac{5}{24} kg

m2 = 0.208kg

Thus, the mass m2 is 0.208 kg.

_____________________________________________________

 3) In the third case :

Force,  F = 5 N

Total Mass,  m = m1 + m2

= 0.625 + 0.208

= 0.833 kg

And, Acceleration,  a = ? (To be calculated)

Now,

putting these values in the relation:

 F = m × a

we get:

 5 = 0.833 × a

a = \frac{5}{0.833}

a =  6 m/s^2

Thus, if both the masses are tied together, then the acceleration would be  6 m/s^2

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