Question

Challenge For you☺️

Find the dimension of a/b in p=a-t^2/bx here, P= pressure
x= Displacement.

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Answer 1

Answer:

• The dimensions of a/b in the equation P=a-t2/bx where P is pressure, x is distance and t is time are.

Explanation:

$. A = MLT-2 ÷ L2 A = ML-1 T-2. P = T2 ÷ BX ML-1T-2 = T2 ÷ B L. ML-1 T-2 × L ÷ T2 = B MT-4 = B A÷ B = ML-1 T-2 ÷ MT-4. A ÷ B = L-1 T 2$

Answer 2

Answer:

here is your answer ˙❥˙

Given :

P= a-t²/bx, where P = Pressure, x= Displacement

To find:

the dimension of a/b

The dimension of a should be equal to the dimension of t².

so, [a]= [T²]

silly the dimension of P should be equal to the dimension of a/bx and t²/bx.

so,

[P]= [ a/bx]= [ t²/bx]

here,

we consider [P]= [t²/bx]

[b]= [t²/px]

= [ T²/ ML-¹ T-²L]

[b]=. [ M-¹ T⁴]

Now,

a/b= T²/M-¹ T⁴= MT-²

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