Question

#CHALLENGEFORUOUALL
DO IT CORRECT!

Answer 1

Step-by-step explanation:

these are your answers

just the sixth one I was not able to do but I am trying and the rest I have tried to do please let me know they are right or wrong

sorry bro I by mistake reported you

Answer 2

Answer:

#CHALLENGEFORUOUALL

#Challengeaccepted(^～^)

Step-by-step explanation:

question1

x²-(12-2)x-24

(x²-12x)+(2x-24)

x(x-12) +2(x-12)

(x-2)(x-12)

que2

2x^2+7x+1

= 2x^2+6x+x+3

=2x(x+3)+1(x+3)

=(2x+1)(x+3)

ques 4

27p^3 - 1/216 - 9/2p^2 + 1/4p

= (3p)^3 - (1/6)^3 - 9/2p^2 + 1/4p

= (3p - 1/6)[(3p)^2 + p/2 + 1/36)] - (3p/2)(3p - 1/6)

= (3p - 1/6)(9p^2 + p/2 + 1/36 - 3p/2)

= (3p - 1/6)(9p^2 - 2p/2 + 1/36)

= (3p - 1/6)(9p^2 - p + 1/36)

= (3p - 1/6)(3p - 1/6)(3p - 1/6)

= (3p - 1/6)^3

ishita (isuu) Ques 3, 5, 6, 7, 8, 9 and 10 are attached .......

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