Question

Chandra and Radha run a race around a circular track. The total length of the circular track is 308 meters. At the half way point, Radha trips and falls down. Chandra who was at the three-fourth mark at this time, runs back to help Radha. What is the magnitude of Chandra’s displacement?

Answer 1

Hii❤~

We know that,

speed  = distance/time

17 = x/t

x = 17t

For second:

Distance = 391 - x

speed = 23 m/s

time  = t

speed = distance/time

23 = (391 - x)/t

23t = 391 - x

putting  x = 17t

23t = 391 - 17t

3t + 17t = 391

40t = 391

t =  391/40

t =  9.77 second

HOPE IT HELPS

Answer 2

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