Question

please solve using properties of proportion

Answer 1

Answer:

$x = 0 \: \: \: \: \: \: \: \: x = \frac{1}{2}$

Step-by-step explanation:

$\frac{ {x}^{2} + x - 3}{x - 3} = \frac{4 {x}^{2} + 3x - 2}{3x - 2} \\ \\ \frac{ {x}^{2} }{x - 3} + 1 = \frac{4 {x}^{2} }{3x - 2} + 1 \\ \\ \frac{ {x}^{2} }{x - 3} = \frac{4 {x}^{2} }{3x - 2} \\ \\ {x}^{2} = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{1}{x - 3} = \frac{1}{3x - 2} \\ \\ \\ \\ \\ x = 0 \: \: \: \: \: \: \: \: \: \: \: x - 3 = 3x - 2 \\ \\ x = 0 \: \: \: \: \: \: \: \: \: x - 3x = 3 - 2 \\ \\ \\ x = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 2x = - 1 \\ \\ \\ x = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: x = \frac{1}{2}$