Question

change cot theta in terms of sin theta

Answer 1

Since, we know, cotΘ = cosΘ / sinΘ

and, cos²(x) = 1 - sin²(x)

⇒cos(x) = ±√{1 - sin²(x)}

Therefore,

cot(x) = ±√{1- sin²(x)}/sin(x)

Answer 2

Answer:

cot theta = $\frac{cos∅}{sin∅}$

and cos∅ can be written as= $\sqrt{1-sinx^{2}∅ }$

so cot theta =  $\frac{\sqrt{1-sinx^{2} ∅} }{sin∅}$

Hope this is helpful

Step-by-step explanation: